Traveler100 61
Ottawa
Ottawa
bytheway 74
Zeist
Zeist
freke 47
Sint-Niklaas
Sint-Niklaas
Sleepy3 36
Houston
Houston
Nikauchi 39
Angarsk
Angarsk
runnerking 53
Antwerpen
Antwerpen
English
Spanish
German
Japanese
Swedish
Displaying posts 1
to 10
of 33.
Well, the "proper" way involves using something called Lambert's W function, but we can cheat a little bit and look at where the graphs of x^2 and 2^x intersect on a graphing calculator :)
Another hint: it's negative and irrational.
2 and 4. I dunno about the third! xD
Hey, I have a math challenge for you: find all the real number solutions of x^2=2^x.
I'll give you a hint: there are 3 of them.
I'll give you a hint: there are 3 of them.
Thanks for dropping by my profile!
Please Sign In
or Join for Free
to view the rest of this profile.